set
1、set 的创建
set1=set([123,456,789])
print(set1){456, 123, 789}set1=set([123,456,789,123,123])
print(set1){456, 123, 789}2、set 添加元素
3、set 删除元素
4、set 的运用
Last updated
set1=set([123,456,789])
print(set1){456, 123, 789}set1=set([123,456,789,123,123])
print(set1){456, 123, 789}Last updated
set1=set([123,456,789])
print(set1)
set1.add(100)
print(set1)
set1.add(100)
print(set1){456, 123, 789}
{456, 123, 100, 789}
{456, 123, 100, 789}set1=set([123,456,789])
print(set1)
set1.remove(456)
print(set1){456, 123, 789}
{123, 789}set1=set('hello')
set2=set(['p','y','y','h','o','n'])
print(set1)
print(set2)
# 交集 (求两个 set 集合中相同的元素)
set3=set1 & set2
print('\n交集 set3:')
print(set3)
# 并集 (合并两个 set 集合的元素并去除重复的值)
set4=set1 | set2
print('\n并集 set4:')
print(set4)
# 差集
set5=set1 - set2
set6=set2 - set1
print('\n差集 set5:')
print(set5)
print('\n差集 set6:')
print( set6)
# 去除海量列表里重复元素,用 hash 来解决也行,只不过感觉在性能上不是很高,用 set 解决还是很不错的
list1 = [111,222,333,444,111,222,333,444,555,666]
set7=set(list1)
print('\n去除列表里重复元素 set7:')
print(set7)
{'h', 'l', 'e', 'o'}
{'h', 'n', 'o', 'y', 'p'}
交集 set3:
{'h', 'o'}
并集 set4:
{'h', 'p', 'n', 'e', 'o', 'y', 'l'}
差集 set5:
{'l', 'e'}
差集 set6:
{'p', 'y', 'n'}
去除列表里重复元素 set7:
{555, 333, 111, 666, 444, 222}